(2x^2 -17x-38) / (2x+3)=

Asked by AnneS2 on 05 Aug 05:40

Last updated by anonymous on 06 Aug 12:48

Answered by CherieS on 06 Aug 12:48

(2x^2 -17x-38) / (2x+3)=x-10 R. -8

(2x+3)(x-10 )

(2x)(x) (2x)(-10) (3)(x) (3)(-10)

2x^2 -10x +3x -30

2x^2 -7x -30

-(2x^2-7x-30)=-2x^2+7x+30

2x^2 -17x-38

-2x^2+7x+30

-8