2b+v+z = 11 and 3b+5v+5z = 34 and 5b+6v+3z = 42 Solve each system of equations

2b+v+z = 11

2b-2b+v+z = 11-2b

v-v+z = 11-2b-v

z = 11-2b-v

3b+5v+5z = 34

3b+5v+5(11-2b-v) = 34

3b+5v+5(11) (5)(-2b) (5)(-v) = 34

3b+5v+55-10b-5v=34

55-7b=34

55-7b-55=34-55

-7b=-21

-7b/-7=-21/-7

b=3

v=4

z = 11-2(3)-4

z=11-6-4=1

z = 11-2b-v

5b+6v+3z = 42

5(3)+6v+3(11-2b-v) = 42

5(3)+6v+3(11) (3)(-2b) (3)(-v) = 42

15+6v+33-18-3v=42

15+3v+33-18=42

3v+30=42

3v+30-30=42-30

3v=12

3v/3=12/3

v=4