1x^2 - 8x + 15 = 0 Solve for x

Asked by AnneS2 12 years ago 5/10/2013 5:00 AM

Last updated by anonymous 12 years ago 5/12/2013 12:12 PM

Answered by CherieS 12 years ago 5/12/2013 12:12 PM

1x^2 - 8x + 15 = 0

(x )(x ) ( -5)( -3)=0

(x-5) (x-3) = 0

Solve:

(x-5)=0

x-5+5=0+5

x=5

Solve:

(x-3) = 0

x-3+3=0+3

x=3