Math

1x^2 - 7x - 8 = 0

Asked by AnneS2 on 16 Mar 04:24

Last updated by anonymous on 17 Mar 13:46

1 Answers

Log in to answer

Answered by CherieS on 17 Mar 13:46

x^2 = 7 x+8 (x-8) (x+1) = 0 -81/4 + (-7/2 + x)^2 == 0

x=-1

x=8