Math

1x^2 - 2x - 63 = 0 Solve for x

Asked by AnneS2 on 10 May 05:01

Last updated by anonymous on 12 May 12:07

1 Answers

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Answered by CherieS on 12 May 12:07

1x^2 - 2x - 63 = 0

(x )(x ) ( -9)( +7)=0

(x-9) (x+7) = 0

Solve:

(x-9)=0

x-9+9=0+9

x=9

Solve:

(x+7) = 0

x+7-7=0-7

x=-7