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> 1x^2 + 7x - 18 = 0
Math
1x^2 + 7x - 18 = 0
Asked by
AnneS2
on 16 Mar 04:18
Last updated by
anonymous
on 17 Mar 14:02
1
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Answered by
CherieS
on 17 Mar 14:02
x (x+7) = 18 (x-2) (x+9) = 0
-121/4 + (7/2 + x)^2 = 0
x=-9
x=2