Math 1x^2 + 7x + 12 = 0 Factor and solve Asked by AnneS2 on 27 Sep 07:20 Last updated by anonymous on 28 Sep 10:42
1x^2 + 7x + 12 = 0 (x )(x ) ( +3)( +4)=0 (x+3) (x+4) = 0 Solve: (x+3) =0 x+3-3 =0-3 x=-3 Solve: (x+4) = 0 x+4-4 = 0-4 x=-4