Math
1^3 + (7^2 + 9 - 4^2 + 8)=

Asked by
AnneS2
Last updated by
anonymous
PEMDAS=(), exponents, *, /, +, -
=1^3 + (7^2 + 9 - 4^2 + 8)
=1^3 + (49 + 9 - 4^2 + 8)
=1^3 + (49 + 9 - 16 + 8)
=1^3 + (58 - 16 + 8)
=1^3 + (42 + 8)
=1^3 + (50)
=1 + (50)
=51