Math

10b^2 =27b-18 Solve

Asked by AnneS2 on 15 May 05:28

Last updated by anonymous on 16 May 12:11

1 Answers

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Answered by CherieS on 16 May 12:11

10b^2 =27b-18

10b^2-27b=27b-18-27b

10b^2-27b=-18

10b^2-27b+18=-18+18

10b^2-27b+18=0

(2b )(5b ) ( -3)( -6)=0

(2 b-3) (5 b-6) = 0

Solve:

(2 b-3)=0

2b-3+3=0+3

2b=3

2b/2=3/2

b=3/2

Solve:

(5 b-6) = 0

5b-6+6=0+6

5b=6

5b/5=6/5

b=6/5