(1 * 4^2 - 8) - 2^3 + 4=

Asked by AnneS2 12 years ago 8/18/2013 1:07 AM

Last updated by anonymous 12 years ago 8/20/2013 7:09 AM

Answered by CherieS 12 years ago 8/20/2013 7:09 AM

PEMDAS=(), exponents, *,/, +, -

=(1 * 4^2 - 8) - 2^3 + 4

=(1 * 16 - 8) - 2^3 + 4

=(16 - 8) - 2^3 + 4

=(8) - 2^3 + 4

=(8) - 8 + 4

=0+4