Math

-1x^2 + 1x + 12 = 0 Solve for x

Asked by AnneS2 on 10 May 05:03

Last updated by anonymous on 12 May 12:01

1 Answers

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Answered by CherieS on 12 May 12:01

-1x^2 + 1x + 12 = 0

-1(x^2-1x-12)=0

-1(x-4) (x+3) = 0

Solve:

-1(x-4)=0

(-1)(x) (-1)(-4)=0

-1x+4=0

-1x+4-4=0-4

-1x=-4

-1x/-1=-4/-1

x=4

Solve:

-1(x+3) = 0

(-1)(x) (-1)(3)=0

-1x-3=0

-1x-3+3=0+3

-1x=3

-1x/-1=3/-1

x=-3